Messages in this thread | | | Date | Tue, 31 Oct 2000 11:15:53 -0500 | From | Vladislav Malyshkin <> | Subject | Re: test10-pre7 |
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Hi, Peter, You can easily remove duplicates in object files without sorting. You can just use a shell written function. This is an example of such function (bash written). It removes the duplicates from the argument and prints the result to stdout. No sorting used.
# This function removes duplicates from a string remove_duplicates() { if [ $# -ne 1 ]; then echo "usage: remove_duplicates string" 1>&2 exit 1 fi str="" for tmpvar1 in $1 ; do flag_found=0 for tmpvar2 in $str ; do if [ "${tmpvar1}" = "${tmpvar2}" ]; then flag_found=1 break fi done if [ "${flag_found}" -eq 0 ]; then str="${str} ${tmpvar1}" fi done echo "${str}" return 0 }
# This is a usage example. x="`remove_duplicates \"a b c d e a b c\"`" echo "$x"
Vladislav
---Peter Samuelson wrote: >> And it should make all this FIRST/LAST object file mockery a total >> non-issue, because the whole concept turns out to be completely >> unnecessary. >> >> Is there anything that makes this more complex than what I've >> outlined above? > >One thing. The main benefit of $(sort), which I haven't heard you >address yet, is to remove duplicate files. Think about 8390.o, and how >many net drivers require it. There are two ways to handle this: > > obj-$(CONFIG_WD80x3) += wd.o 8390.o > obj-$(CONFIG_EL2) += 3c503.o 8390.o > obj-$(CONFIG_NE2000) += ne.o 8390.o > obj-$(CONFIG_NE2_MCA) += ne2.o 8390.o > obj-$(CONFIG_HPLAN) += hp.o 8390.o
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