Messages in this thread | | | Date | Mon, 21 Sep 2009 23:22:41 +1000 | From | Peter Williams <> | Subject | sched: Am I missing something? |
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Or is the line:
p->prio = effective_prio(p);
in wake_up_new_task() an expensive no op.
As far as I can tell from reading the code, it will always be the case that EITHER rt_prio(p->prio) is true OR p->prio == p->normal_prio when this call is made and, in either case, the value of p->prio will be unchanged. In addition, when this call is made p->normal_prio is already equal to to normal_prio(p), so the side effects of the function (setting p->normal_prio) are also unnecessary.
Am I correct or have I missed something?
Peter -- Peter Williams pwil3058@bigpond.net.au
"Learning, n. The kind of ignorance distinguishing the studious." -- Ambrose Bierce
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