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What version of Linux are you using ? What I see is the following:
Thread1
Thread1
Thread1
Thread1
Thread1
Thread2
Thread2
Thread2
Thread2
Thread2

Also, it is NOT unrealistic to expect perfect alternation. The definition
of sched_yield in the manpage says that sched_yield() puts the thread under
question last in the run queue. So perfect alternation should have occurred.
I've also tested the code on Solaris - there is perfect alternation there.


- Mohit


-----Original Message-----
From: David Schwartz [mailto:davids@webmaster.com]
Sent: Sunday, February 04, 2001 3:09 AM
To: Mohit Aron; linux-kernel@vger.kernel.org
Subject: RE: system call sched_yield() doesn't work on Linux 2.2



The program you attached worked perfectly for me. You need to
'fflush(stdout);' after each 'printf'. You didn't expect perfect alternation
did you? That's totally unrealistic. You cannot use the scheduler as a
synchronization mechanism.

--

Thread1
Thread1
Thread2
Thread1
Thread1
Thread2
Thread1
Thread2
Thread2
Thread2

--

DS

> -----Original Message-----
> From: linux-kernel-owner@vger.kernel.org
> [mailto:linux-kernel-owner@vger.kernel.org]On Behalf Of Mohit Aron
> Sent: Saturday, February 03, 2001 2:53 PM
> To: linux-kernel@vger.kernel.org
> Subject: system call sched_yield() doesn't work on Linux 2.2
>
>
> Hi,
> the system call sched_yield() doesn't seem to work on Linux
> 2.2. Does
> anyone know of a kernel patch that fixes this ?
>
> Attached below is a small program that uses pthreads and demonstrates that
> sched_yield() doesn't work. Basically, the program creates two
> threads that
> alternatively try to yield CPU to each other.
>
>
> - Mohit
>
>
-
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