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    SubjectRe: {sys_,/dev/}epoll waiting timeout
    Ed Tomlinson wrote:
    > Jamie Lokier wrote:
    >
    > > jtimeout = 0;
    > > if (timeout) {
    > > /* Careful about overflow in the intermediate values */
    > > if ((unsigned long) timeout < MAX_SCHEDULE_TIMEOUT / HZ)
    > > jtimeout = (unsigned long)(timeout*HZ+999)/1000+1;
    > > else /* Negative or overflow */
    > > jtimeout = MAX_SCHEDULE_TIMEOUT;
    > > }
    >
    > Why assume HZ=1000? Would not:
    >
    > timeout = (unsigned long)(timeout*HZ+(HZ-1))/HZ+1;
    >
    > make more sense?

    No, that's silly. Why do you want to multiply by HZ and then divide by HZ?

    -- Jamie
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