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SubjectRe: {sys_,/dev/}epoll waiting timeout
Date
Jamie Lokier wrote:

> jtimeout = 0;
> if (timeout) {
> /* Careful about overflow in the intermediate values */
> if ((unsigned long) timeout < MAX_SCHEDULE_TIMEOUT / HZ)
> jtimeout = (unsigned long)(timeout*HZ+999)/1000+1;
> else /* Negative or overflow */
> jtimeout = MAX_SCHEDULE_TIMEOUT;
> }

Why assume HZ=1000? Would not:

timeout = (unsigned long)(timeout*HZ+(HZ-1))/HZ+1;

make more sense?

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