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SubjectRe: [PATCH V2 2/7] xen/grants: support allocating consecutive grants
From
On 14.05.22 04:34, Boris Ostrovsky wrote:
>
>
> On 5/13/22 1:33 AM, Juergen Gross wrote:
>> On 12.05.22 22:01, Boris Ostrovsky wrote:
>>>
>>> On 5/7/22 2:19 PM, Oleksandr Tyshchenko wrote:
>
>>>> +/* Rebuilds the free grant list and tries to find count consecutive
>>>> entries. */
>>>> +static int get_free_seq(unsigned int count)
>>>> +{
>>>> +    int ret = -ENOSPC;
>>>> +    unsigned int from, to;
>>>> +    grant_ref_t *last;
>>>> +
>>>> +    gnttab_free_tail_ptr = &gnttab_free_head;
>>>> +    last = &gnttab_free_head;
>>>> +
>>>> +    for (from = find_first_bit(gnttab_free_bitmap, gnttab_size);
>>>> +         from < gnttab_size;
>>>> +         from = find_next_bit(gnttab_free_bitmap, gnttab_size, to + 1)) {
>>>> +        to = find_next_zero_bit(gnttab_free_bitmap, gnttab_size,
>>>> +                    from + 1);
>>>> +        if (ret < 0 && to - from >= count) {
>>>> +            ret = from;
>>>> +            bitmap_clear(gnttab_free_bitmap, ret, count);
>>>> +            from += count;
>>>> +            gnttab_free_count -= count;
>>>
>>>
>>> IIUIC we can have multiple passes over this, meaning that the
>>> gnttab_free_count may be decremented more than once. Is that intentional?
>>
>> After the first pass decrementing gnttab_free_cnt, ret will no
>> longer be less than zero, so this can be hit only once.
>
> Oh, yes, of course.
>
>>
>>>
>>>
>>>> +            if (from == to)
>>>> +                continue;
>>>> +        }
>>>> +
>>>> +        while (from < to) {
>>>> +            *last = from;
>>>> +            last = __gnttab_entry(from);
>>>> +            gnttab_last_free = from;
>>>> +            from++;
>>>> +        }
>>>
>>>
>>> I have been looking at this loop and I can't understand what it is doing ;-(
>>> Can you enlighten me?
>>
>> It is recreating the free list in order to have it properly sorted.
>> This is needed to make sure that the free tail has the maximum
>> possible size (you can take the tail off the list without having
>> to worry about breaking the linked list because of references into
>> the tail).
>
>
> So let's say we have the (one-dimensional) table of length 13
>
> idx    ..    2    3  ...  10  11  12
>
> grant       12   11        2  -1   3
>
>
> and gnttab_free_head is 10. I.e. the free list is 2, 12, 3, 11.

You meant 10, 2, 12, 3, 11, I guess?

>
> What will this look like after the 2 iterations of the outer loop?

idx .. 2 3 ... 10 11 12

grant 3 10 11 12 -1

with gnttab_free_head being 2, i.e the free list is now 2, 3, 10, 11, 12.


Juergen
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