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SubjectRe: [PATCH v2 2/4] arm64: Define Documentation/arm64/elf_at_flags.txt
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On 03/04/2019 17:50, Catalin Marinas wrote:
> On Fri, Mar 22, 2019 at 03:52:49PM +0000, Kevin Brodsky wrote:
>> On 18/03/2019 16:35, Vincenzo Frascino wrote:
>>> +2. Features exposed via AT_FLAGS
>>> +--------------------------------
>>> +
>>> +bit[0]: ARM64_AT_FLAGS_SYSCALL_TBI
>>> +
>>> + On arm64 the TCR_EL1.TBI0 bit has been always enabled on the arm64
>>> + kernel, hence the userspace (EL0) is allowed to set a non-zero value
>>> + in the top byte but the resulting pointers are not allowed at the
>>> + user-kernel syscall ABI boundary.
>>> + When bit[0] is set to 1 the kernel is advertising to the userspace
>>> + that a relaxed ABI is supported hence this type of pointers are now
>>> + allowed to be passed to the syscalls, when these pointers are in
>>> + memory ranges privately owned by a process and obtained by the
>>> + process in accordance with the definition of "valid tagged pointer"
>>> + in paragraph 3.
>>> + In these cases the tag is preserved as the pointer goes through the
>>> + kernel. Only when the kernel needs to check if a pointer is coming
>>> + from userspace an untag operation is required.
>> I would leave this last sentence out, because:
>> 1. It is an implementation detail that doesn't impact this user ABI.
>> 2. It is not entirely accurate: untagging the pointer may be needed for
>> various kinds of address lookup (like finding the corresponding VMA), at
>> which point the kernel usually already knows it is a userspace pointer.
> I fully agree, the above paragraph should not be part of the user ABI
> document.
>
>>> +3. ARM64_AT_FLAGS_SYSCALL_TBI
>>> +-----------------------------
>>> +
>>> +From the kernel syscall interface prospective, we define, for the purposes
>>> +of this document, a "valid tagged pointer" as a pointer that either it has
>>> +a zero value set in the top byte or it has a non-zero value, it is in memory
>>> +ranges privately owned by a userspace process and it is obtained in one of
>>> +the following ways:
>>> + - mmap() done by the process itself, where either:
>>> + * flags = MAP_PRIVATE | MAP_ANONYMOUS
>>> + * flags = MAP_PRIVATE and the file descriptor refers to a regular
>>> + file or "/dev/zero"
>>> + - a mapping below sbrk(0) done by the process itself
>> I don't think that's very clear, this doesn't say how the mapping is
>> obtained. Maybe "a mapping obtained by the process using brk() or sbrk()"?
> I think what we mean here is anything in the "[heap]" section as per
> /proc/*/maps (in the kernel this would be start_brk to brk).
>
>>> + - any memory mapped by the kernel in the process's address space during
>>> + creation and following the restrictions presented above (i.e. data, bss,
>>> + stack).
>> With the rules above, the code section is included as well. Replacing "i.e."
>> with "e.g." would avoid having to list every single section (which is
>> probably not a good idea anyway).
> We could mention [stack] explicitly as that's documented in the
> Documentation/filesystems/proc.txt and it's likely considered ABI
> already.
>
> The code section is MAP_PRIVATE, and can be done by the dynamic loader
> (user process), so it falls under the mmap() rules listed above. I guess
> we could simply drop "done by the process itself" here and allow
> MAP_PRIVATE|MAP_ANONYMOUS or MAP_PRIVATE of regular file. This would
> cover the [heap] and [stack] and we won't have to debate the brk() case
> at all.

That's probably the best option. I initially used this wording because I was worried
that there could be cases where the kernel allocates "magic" memory for userspace
that is MAP_PRIVATE|MAP_ANONYMOUS, but in fact it's probably not the case (presumably
such mapping should always be done via install_special_mapping(), which is definitely
not MAP_PRIVATE).

> We probably mention somewhere (or we should in the tagged pointers doc)
> that we don't support tagged PC.

I think that Documentation/arm64/tagged-pointers.txt already makes it reasonably
clear (anyway, with the architecture not supporting it, you can't expect much from
the kernel).

Kevin

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