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SubjectRe: detecting integer constant expressions in macros
On 2018-03-21 00:08, Linus Torvalds wrote:
> On Tue, Mar 20, 2018 at 3:13 PM, Uecker, Martin
> <> wrote:
>> here is an idea:
> That's not "an idea".
> That is either genius, or a seriously diseased mind.
> I can't quite tell which.
>> a test for integer constant expressions which returns an
>> integer constant expression itself which should be suitable
>> for passing to __builtin_choose_expr might be:
>> #define ICE_P(x) (sizeof(int) == sizeof(*(1 ? ((void*)((x) * 0l)) : (int*)1)))

Wow. This is absolutely awesome.

>> This also does not evaluate x itself on gcc although this is
>> not guaranteed by the standard. (And I haven't tried any older
>> gcc.)
> Oh, I think it's guaranteed by the standard that 'sizeof()' doesn't
> evaluate the argument value, only the type.

Even if there's some hypothetical scenario where x ends up containing
something of variably-modified type, could one just use 0? instead of 1?
. That doesn't affect the type of the whole expression.

> I'm in awe of your truly marvelously disgusting hack. That is truly a
> work of art.

I'm not really worthy of commenting or trying to improve on this, but I
think it's important that 'git blame' will forever give Martin the
credit for this, so two minor suggestions:

- Cast (x) to (long) to allow x to have type u64 on a 32-bit platform
without giving "warning: cast to pointer from integer of different
size". That also allows x to have pointer type (it's theoretically
useful to take max() of two pointers into an array), and not so
important for the kernel, floating point type.

- Maybe use (int*)4 to avoid the compiler complaining about creating a
non-aligned pointer.

> I'm sure it doesn't work or causes warnings for various reasons, but
> it's still a thing of beaty.

I tried putting the below ugly test code through various gcc versions.
In no cases could I get different optimization options to generate
different results. I also couldn't get -Wall -Wextra to produce any
warnings that wasn't just due to the silly input (i.e., yes, I know I
have a comma expression with no side effects....). Most importantly,
ICE_P was always accepted as an ICE itself. Everything from 4.6 onwards
gives the same and expected output, namely 1 in the first four lines, 0
otherwise. gcc 4.4 instead produces this:

4 1
sizeof(long) 1
5ull - 3u 1
3.2 1
square(2) 0
square(argc) 0
squarec(2) 1
squarec(argc) 1
1+argc-argc 1
1+argc+argc+1-argc-argc 1
bignum() - 1 0
0*bignum() 0
0*bignumc() 1
sizeof(foo) 0
p 1
p < q 1
p++ 0
main 1
malloc(8) 0
v = malloc(8) 0
v 1
x++ 0
y++ 0
(3, 2, 1) 0
({x++; 0; }) 0
({square(y--); 0; }) 0
(square(x), 3) 0
(squarec(x), 3) 0
({squarec(x); 3;}) 0
({squarec(x);}) 1

So it seems to accept/treat (x)*0l as NULL as long as x has no
side-effects - where a function call is treated as having side effects
unless the function is declared with the const attribute,
comma-expressions are hard-coded as having side-effects [and what else
would they be good for, so that's not totally unreasonable...], and
statement expressions have side effects if they have more than one


#include <stdio.h>
#include <stdlib.h>

static inline __attribute__((__const__)) unsigned squarec(unsigned n)
return n*n;

static inline unsigned square(unsigned n)
return n*n;

static inline unsigned long long bignum(void)
return 1000000000000ULL;

static inline __attribute__((__const__)) unsigned long long bignumc(void)
return 1000000000000ULL;

/* #define ICE_P(x) (sizeof(int) == sizeof(*(1 ? ((void*)((long)(x) *
0l)) : (int*)1))) */
#define ICE_P(x) (__builtin_types_compatible_p(typeof(0 ?
((void*)((long)(x) * 0l)) : (int*)1), int*))

#define t(x) printf("%-20s\t%d\n", #x, __builtin_choose_expr(ICE_P(x),
1, 0))

int main(int argc, char *argv[])
char foo[argc++];
char **p, **q;
int x = 5, y = 8;
void *v;

p = &argv[3];
q = &argv[6];

t(5ull - 3u);
t(bignum() - 1);
t(p < q);
t(v = malloc(8));
t((3, 2, 1));
t(({x++; 0; }));
t(({square(y--); 0; }));
t((square(x), 3));
t((squarec(x), 3));
t(({squarec(x); 3;}));

/* Shutup distracting warnings. */
if (argc > 100000) {
printf("%llu", square(argc) + squarec(argc) + bignum() + bignumc());

return 0;

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