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SubjectRe: [PATCH 1/2] rcu: Transform kfree_rcu() into kvfree_rcu()
On Tue, 6 Feb 2018 18:06:33 +0300
Kirill Tkhai <> wrote:

> There are kfree_rcu() and vfree_rcu() defined below, and they will give
> compilation error if someone tries to implement one more primitive with
> the same name.

Ah, I misread the patch. I was thinking you were simply replacing
kfree_rcu() with kvfree_rcu(), but now see the macros added below it.

> We may add a comment, but I'm not sure it will be good if people will use
> unpaired brackets like:
> obj = kmalloc(..)
> kvfree_rcu(obj,..)
> after they read such a commentary that it works for both vmalloc and kmalloc.
> After this unpaired behavior distribute over the kernel, we won't be able
> to implement some debug on top of this defines (I'm not sure it will be really
> need in the future, but anyway).
> Though, we may add a comment forcing use of paired bracket. Something like:
> /**
> * kvfree_rcu() - kvfree an object after a grace period.
> This is a primitive for objects allocated via kvmalloc*() family primitives.
> Do not use it to free kmalloc() and vmalloc() allocated objects, use kfree_rcu()
> and vfree_rcu() wrappers instead.
> How are you about this?

Never mind, I missed the adding of kfree_rcu() at the bottom, and was
thinking that we were just using kvfree_rcu() for everything.

That's what I get for looking at patches before my first cup of
coffee ;-)

If you want to add a comment, feel free, but taking a second look, I
don't feel it is necessary.

-- Steve

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