Messages in this thread | | | Date | Thu, 20 Jul 2017 15:03:58 -0700 | From | Ram Pai <> | Subject | Re: [RFC v6 01/62] powerpc: Free up four 64K PTE bits in 4K backed HPTE pages |
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On Thu, Jul 20, 2017 at 11:21:51AM +0530, Aneesh Kumar K.V wrote: > > ..... > > > /* > > @@ -116,8 +104,8 @@ int __hash_page_4K(unsigned long ea, unsigned long access, unsigned long vsid, > > * On hash insert failure we use old pte value and we don't > > * want slot information there if we have a insert failure. > > */ > > - old_pte &= ~(H_PAGE_HASHPTE | H_PAGE_F_GIX | H_PAGE_F_SECOND); > > - new_pte &= ~(H_PAGE_HASHPTE | H_PAGE_F_GIX | H_PAGE_F_SECOND); > > + old_pte &= ~(H_PAGE_HASHPTE); > > + new_pte &= ~(H_PAGE_HASHPTE); > > goto htab_insert_hpte; > > } > > With the current path order and above hunk we will breaks the bisect I guess. With the above, when > we convert a 64k hpte to 4khpte, since this is the first patch, we > should clear that H_PAGE_F_GIX and H_PAGE_F_SECOND. We still use them > for 64k. I guess you should move this hunk to second patch.
true. it should move to the next patch. Will fix it. RP
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