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SubjectRe: [PATCH V6] sched/fair: Remove group imbalance from calculate_imbalance()
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Hi Jeffrey,

On 13/07/17 20:55, Jeffrey Hugo wrote:
> The group_imbalance path in calculate_imbalance() made sense when it was
> added back in 2007 with commit 908a7c1b9b80 ("sched: fix improper load
> balance across sched domain") because busiest->load_per_task factored into
> the amount of imbalance that was calculated. Beginning with commit
> dd5feea14a7d ("sched: Fix SCHED_MC regression caused by change in sched
> cpu_power"), busiest->load_per_task is not a factor in the imbalance
> calculation, thus the group_imbalance path no longer makes sense.

You're referring here to the use of 'sds->max_load -
sds->busiest_load_per_task' in the calculation of max_pull which got
replaced by load_above_capacity with dd5feea14a7d?

I still wonder if the original code (908a7c1b9b80)

if (group_imb)
busiest_load_per_task = min(busiest_load_per_task, avg_load);

had something to do with the following:

if (max_load <= busiest_load_per_task)
goto out_balanced;

> The group_imbalance path can only affect the outcome of
> calculate_imbalance() when the average load of the domain is less than the
> original busiest->load_per_task. In this case, busiest->load_per_task is
> overwritten with the scheduling domain load average. Thus
> busiest->load_per_task no longer represents actual load that can be moved.
>
> At the final comparison between env->imbalance and busiest->load_per_task,
> imbalance may be larger than the new busiest->load_per_task causing the
> check to fail under the assumption that there is a task that could be
> migrated to satisfy the imbalance. However env->imbalance may still be
> smaller than the original busiest->load_per_task, thus it is unlikely that
> there is a task that can be migrated to satisfy the imbalance.
> Calculate_imbalance() would not choose to run fix_small_imbalance() when we
> expect it should. In the worst case, this can result in idle cpus.
>
> Since the group imbalance path in calculate_imbalance() is at best a NOP
> but otherwise harmful, remove it.
>

IIRC the topology you had in mind was MC + DIE level with n (n > 2) DIE
level sched groups.

Running the testcase 'taskset 0x05 '2 always running task'' (both tasks
starting on cpu0) on your machine shows the issue since with your
previous patch [1] "sched/fair: Fix load_balance() affinity redo path"
we now propagate 'group imbalance' from MC level to DIE level and since
you have n > 2 you lower busiest->load_per_task in this group_imbalanced
related if condition all the time and env->imbalance stays too small to
let one of these tasks migrate to cpu2.

Tried to test it on an Intel i5-3320M (2 cores x 2 HT) with rt-app (2
always running cfs task with affinity 0x05 for 2*x ms and one rt task
affine to 0x04 for x ms):

# cat /proc/schedstat | grep ^domain | awk '{ print $1" "$2}'
domain0 03
domain1 0f
domain0 03
domain1 0f
domain0 0c
domain1 0f
domain0 0c
domain1 0f

but here the prefer_sibling handling (group overloaded) eclipses 'group
imbalance' the moment one of the cfs tasks can go to cpu2 so the if
condition you got rid of is a nop.

I wonder if it is fair to say that your fix helps multi-cluster
(especially with n > 2) systems without SMT and with your first patch
[1] for this specific, cpu affinity restricted test cases.

> Co-authored-by: Austin Christ <austinwc@codeaurora.org>
> Signed-off-by: Jeffrey Hugo <jhugo@codeaurora.org>
> Tested-by: Tyler Baicar <tbaicar@codeaurora.org>
> ---

Reviewed-by: Dietmar Eggemann <dietmar.eggemann@arm.com>

>
> [v6]
> -Added additional history clarification to commit text
>
> kernel/sched/fair.c | 9 ---------
> 1 file changed, 9 deletions(-)
>
> diff --git a/kernel/sched/fair.c b/kernel/sched/fair.c
> index 84255ab..3600713 100644
> --- a/kernel/sched/fair.c
> +++ b/kernel/sched/fair.c
> @@ -7760,15 +7760,6 @@ static inline void calculate_imbalance(struct lb_env *env, struct sd_lb_stats *s
> local = &sds->local_stat;
> busiest = &sds->busiest_stat;
>
> - if (busiest->group_type == group_imbalanced) {
> - /*
> - * In the group_imb case we cannot rely on group-wide averages
> - * to ensure cpu-load equilibrium, look at wider averages. XXX
> - */
> - busiest->load_per_task =
> - min(busiest->load_per_task, sds->avg_load);
> - }
> -
> /*
> * Avg load of busiest sg can be less and avg load of local sg can
> * be greater than avg load across all sgs of sd because avg load
>

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