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SubjectRe: [PATCH v3 4/6] sched/rt: fast switch to maximum frequency when RT tasks are scheduled
Hi Vincent,

On 06-Dec 10:39, Vincent Guittot wrote:
> Hi Patrick,
>
> On 30 November 2017 at 12:47, Patrick Bellasi <patrick.bellasi@arm.com> wrote:

[...]

> > static void dequeue_task_rt(struct rq *rq, struct task_struct *p, int flags)
> > @@ -1564,6 +1564,9 @@ pick_next_task_rt(struct rq *rq, struct task_struct *prev, struct rq_flags *rf)
> >
> > p = _pick_next_task_rt(rq);
> >
> > + /* Kick cpufreq (see the comment in kernel/sched/sched.h). */
>
> p is null when there is no rt task to pick.
> You should test this condition before calling cpufreq_update_util

Mmm... for what I see, from the above function's implementation,
_pick_next_task_rt() is always returning a valid pointer to an RT
task.

The above call does a:

p->se.exec_start = rq_clock_task(rq);

right before returning, and there is also a BUG_ON(!rt_se) in the
previous RT tasks scanning loop.

Am I missing something?

> > + cpufreq_update_util(rq, SCHED_CPUFREQ_RT);
> > +
> > /* The running task is never eligible for pushing */
> > dequeue_pushable_task(rq, p);

[...]

> > @@ -2317,6 +2323,9 @@ static void set_curr_task_rt(struct rq *rq)
> >
> > p->se.exec_start = rq_clock_task(rq);
> >
> > + /* Kick cpufreq (see the comment in kernel/sched/sched.h). */
> > + cpufreq_update_util(rq, SCHED_CPUFREQ_RT);
>
> Is this change linked to the "- when a task is set to be RT" in the
> commit message ?
>
> I can't see a situation where this is call without the previous one.
> AFAICT, enqueue_task_rt will be called before each call to this
> function

Yeah, you right, in core.c the pattern seems to always be:

if (queued)
enqueue_task()
if (running)
set_curr_task()

I'll remove this chunk from the next version.

>
> > +
> > /* The running task is never eligible for pushing */
> > dequeue_pushable_task(rq, p);
> > }

Thanks for the review!

--
#include <best/regards.h>

Patrick Bellasi

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