Messages in this thread | | | Date | Tue, 1 Jul 2014 13:06:22 +0100 | From | Russell King - ARM Linux <> | Subject | Re: [PATCH] regulator: core: Still free GPIOs using gpio_free() |
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On Tue, Jul 01, 2014 at 12:55:26PM +0100, Mark Brown wrote: > From: Mark Brown <broonie@linaro.org> > > Even though we mostly use GPIO descriptors internally we still use > gpio_request_one() to request so we need to pair that with gpio_free() to > release the GPIO. > > Reported-by: Linus Walleij <linus.walleij@linaro.org> > Signed-off-by: Mark Brown <broonie@linaro.org>
This doesn't explain the reason... I see the current GPIO code doing this:
void gpio_free(unsigned gpio) { gpiod_free(gpio_to_desc(gpio)); } EXPORT_SYMBOL_GPL(gpio_free);
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