Messages in this thread | | | Date | Wed, 28 May 2014 17:11:49 -0500 | Subject | Re: [PATCH 11/16] byteorder: provide a linux/byteorder.h with {be, le}_to_cpu() and cpu_to_{be, le}() macros | From | Cody P Schafer <> |
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On Wed, May 28, 2014 at 5:05 PM, Cody P Schafer <dev@codyps.com> wrote: > On Wed, May 28, 2014 at 3:45 AM, David Laight <David.Laight@aculab.com> wrote: >> From: Cody P Schafer >>> Rather manually specifying the size of the integer to be converted, key >>> off of the type size. Reduces duplicate size info and the occurance of >>> certain types of bugs (using the wrong sized conversion). >> ... >>> +#define be_to_cpu(v) \ >>> + __builtin_choose_expr(sizeof(v) == sizeof(uint8_t) , v, \ >>> + __builtin_choose_expr(sizeof(v) == sizeof(uint16_t), be16_to_cpu(v), \ >>> + __builtin_choose_expr(sizeof(v) == sizeof(uint32_t), be32_to_cpu(v), \ >>> + __builtin_choose_expr(sizeof(v) == sizeof(uint64_t), be64_to_cpu(v), \ >>> + (void)0)))) >> ... >> >> I'm not at all sure that using the 'size' of the constant will reduce >> the number of bugs - it just introduces a whole new category of bugs. > > Certainly, if you mis-size the argument (and thus have missized one of > the variables containing the be value, probably a bug anyhow), there > will be problems. > > I put this interface together because of an actual bug I wrote into > the initial code of the hv_24x7 driver (resized a struct member > without adjusting the be*_to_cpu() sizing). > Having this "auto sizing" macro means I can avoid encoding the size of > a struct field in multiple places.
To clarify, the point I'm making here is that this simply cuts out 1 more place we can screw up endianness conversion sizing.
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