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SubjectRe: [PATCH 07/15 V3] perf, c2c: Add in sort on physid
On Tue, 8 Apr 2014 10:17:58 -0400, Don Zickus wrote:
> On Tue, Apr 08, 2014 at 04:56:25PM +0900, Namhyung Kim wrote:
>> On Mon, 24 Mar 2014 15:36:58 -0400, Don Zickus wrote:
>> > +static int perf_c2c__init(struct perf_c2c *c2c)
>> > +{
>> > + sort__mode = SORT_MODE__PHYSID;
>> > + sort__wants_unique = 1;
>> > + sort_order = "daddr,iaddr,pid,tid";
>> Where are the SORT_MODE__PHYSID, sort__wants_unique and "daddr", "iaddr"
>> sort keys defined?
> In a previous patchset that enables the mmap2 interface.

Ah, missed that.. will look at it soon.

>> Also, more importantly, I think the sort order should contain at least
>> "mem" and "snoop" keys to group samples based on the exact hitm
>> information.
> I can look into it, but after iaddr, pid and tid, sorting on snoop doesn't
> really change anything if I recall. The hitms are scattered across iaddr.

But it doesn't guarantee that all hitms are scattered, right? Also if
it's the case I guess adding more sort keys are not harmful since they
don't even have a chance to test.

I think you can check hist_entry->stat.nr_events always being 1.

>> In my understanding, if two samples are captured at exactly same
>> position with a same data access but different hitm info, they cannot be
>> classified and just use the hitm info of first entry.
> Why? If the first hitm access was local and the second one remote,
> doesn't that indicate the accessed data is being pulled onto different
> nodes?

But "hist_entry" won't have the information after calling
__hists__add__entry() called unless it has 'mem' and 'snoop' sort keys.
Since two samples have same daddr, iaddr, pid and tid, it'd think those
two samples are same and then add stats of second one to the first and
finally discard the second. So first one will have a double weight for
the local hitm case only.

This is the case what I worry about. Am I missing something?


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