Messages in this thread | | | Date | Wed, 05 Feb 2014 15:48:47 +0100 | From | Gregory CLEMENT <> | Subject | Re: [PATCH] clk: add strict of_clk_init dependency check |
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Hi Boris,
On 05/02/2014 10:48, Boris BREZILLON wrote: > The parent dependency check is only available on the first parent of a given > clk. > > Add support for strict dependency check: all parents of a given clk must be > initialized. > > Signed-off-by: Boris BREZILLON <b.brezillon@overkiz.com> > --- > > Hello Gregory, > > This patch adds support for strict check on clk dependencies (check if all > parents specified by an DT clk node are initialized). > > I'm not sure this is what you were expecting (maybe testing the first parent > is what you really want), so please feel free to tell me if I'm wrong. > > Best Regards, > > Boris > > drivers/clk/clk.c | 27 +++++++++++++++++++++------ > 1 file changed, 21 insertions(+), 6 deletions(-) > > diff --git a/drivers/clk/clk.c b/drivers/clk/clk.c > index beb0f8b..6849769 100644 > --- a/drivers/clk/clk.c > +++ b/drivers/clk/clk.c > @@ -2543,22 +2543,37 @@ static int parent_ready(struct device_node *np) > { > struct of_phandle_args clkspec; > struct of_clk_provider *provider; > + int num_parents; > + bool found; > + int i; > > /* > * If there is no clock parent, no need to wait for them, then > * we can consider their absence as being ready > */ > - if (of_parse_phandle_with_args(np, "clocks", "#clock-cells", 0, > - &clkspec)) > + num_parents = of_count_phandle_with_args(np, "clocks", "#clock-cells"); > + if (num_parents <= 0) > return 1; > > - /* Check if we have such a provider in our array */ > - list_for_each_entry(provider, &of_clk_providers, link) { > - if (provider->node == clkspec.np) > + for (i = 0; i < num_parents; i++) { > + if (of_parse_phandle_with_args(np, "clocks", "#clock-cells", i, > + &clkspec)) > return 1; > + > + /* Check if we have such a provider in our array */ > + found = false; > + list_for_each_entry(provider, &of_clk_providers, link) { > + if (provider->node == clkspec.np) { > + found = true; > + break;
Hum this means that as soon as you have one parent then you consider it as ready. It is better of what I have done because I only test the 1st parent. However I wondered if we should go further by ensuring all the parents are ready.
If I am right, there is more than one parent only for the muxer. In this case is it really expected that all the parent are ready?
Thanks,
Gregory
> + } > + } > + > + if (!found) > + return 0; > } > > - return 0; > + return 1; > } > > /** >
-- Gregory Clement, Free Electrons Kernel, drivers, real-time and embedded Linux development, consulting, training and support. http://free-electrons.com
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