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SubjectRe: [RFC 07/23] mm/memblock: debug: correct displaying of upper memory boundary
On Sat, Oct 12, 2013 at 05:58:50PM -0400, Santosh Shilimkar wrote:
> From: Grygorii Strashko <grygorii.strashko@ti.com>
>
> When debugging is enabled (cmdline has "memblock=debug") the memblock
> will display upper memory boundary per each allocated/freed memory range
> wrongly. For example:
> memblock_reserve: [0x0000009e7e8000-0x0000009e7ed000] _memblock_early_alloc_try_nid_nopanic+0xfc/0x12c
>
> The 0x0000009e7ed000 is displayed instead of 0x0000009e7ecfff
>
> Hence, correct this by changing formula used to calculate upper memory
> boundary to (u64)base + size - 1 instead of (u64)base + size everywhere
> in the debug messages.

I kinda prefer base + size because it's easier to actually know the
size but yeah, it should have been [base, base + size) and other
places use base + size - 1 notation so it probably is better to stick
to that. Maybe move this one to the beginning of the series?

Acked-by: Tejun Heo <tj@kernel.org>

Thanks.

--
tejun


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