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SubjectRe: [PATCH 09/16] sched: normalize tg load contributions against runnable time
On Wed, 2012-06-27 at 19:24 -0700, Paul Turner wrote:
> Entities of equal weight should receive equitable distribution of cpu time.
> This is challenging in the case of a task_group's shares as execution may be
> occurring on multiple cpus simultaneously.
> To handle this we divide up the shares into weights proportionate with the load
> on each cfs_rq. This does not however, account for the fact that the sum of
> the parts may be less than one cpu and so we need to normalize:
> load(tg) = min(runnable_avg(tg), 1) * tg->shares
> Where runnable_avg is the aggregate time in which the task_group had runnable
> children.

I remember we had a bit of a discussion on this last time, I thought you
were going to convince me this approximation was 'right'.

Care to still do so.. the rationale used should at least live in a
comment somewhere, otherwise someone will go silly trying to understand
things later on.

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