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Subject[PATCH] ubi: fastmap: Do not free 'ai' in 'scan_all()'
From: Shmulik Ladkani <shmulik.ladkani@gmail.com>

Do not call 'destroy_ai(ai)' at error handling of 'scan_all', since:
- 'ai' is allocated in 'ubi_attach' (the caller of scan_all) and
provided as an argument. It's not scan_all's responsibility to free it
- It is not consistent with scan_all's sister function
'ubi_attach_fastmap()' which does not free the given 'ai'
- It will cause a double free as 'ubi_attach' (the caller of scan_all)
already destroys 'ai' in case of an error

Signed-off-by: Shmulik Ladkani <shmulik.ladkani@gmail.com>
---
- compile tested

diff --git a/drivers/mtd/ubi/attach.c b/drivers/mtd/ubi/attach.c
index 019fbd3..8a339e4 100644
--- a/drivers/mtd/ubi/attach.c
+++ b/drivers/mtd/ubi/attach.c
@@ -1152,11 +1152,11 @@ static int scan_all(struct ubi_device *ubi, struct ubi_attach_info *ai)
sizeof(struct ubi_ainf_peb),
0, 0, NULL);
if (!ai->aeb_slab_cache)
- goto out_ai;
+ return -ENOMEM;

ech = kzalloc(ubi->ec_hdr_alsize, GFP_KERNEL);
if (!ech)
- goto out_ai;
+ return -ENOMEM;

vidh = ubi_zalloc_vid_hdr(ubi, GFP_KERNEL);
if (!vidh)
@@ -1218,8 +1218,6 @@ out_vidh:
ubi_free_vid_hdr(ubi, vidh);
out_ech:
kfree(ech);
-out_ai:
- destroy_ai(ai);
return err;
}


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