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SubjectRe: [PATCH] avoiding the same resource to be inserted
From
On Wed, Aug 25, 2010 at 7:46 AM, Andrew Morton
<akpm@linux-foundation.org> wrote:
> On Mon, 16 Aug 2010 23:55:38 +0800
> Huang Shijie <shijie8@gmail.com> wrote:
>
>>   If the same resource is inserted to the resource tree
>> (maybe not on purpose), a dead loop will be created. In this situation,
>> The kernel does not report any warning or error       :(
>>
>>   The command below will show a endless print.
>>   #cat /proc/iomem
>
> OK, we shouldn't do that.
>
>>   So, adding the check for the same resource is needed for the stability
>> and reliability of the kernel.
>>
>> Signed-off-by: Huang Shijie <shijie8@gmail.com>
>> ---
>>  kernel/resource.c |    2 +-
>>  1 files changed, 1 insertions(+), 1 deletions(-)
>>
>> diff --git a/kernel/resource.c b/kernel/resource.c
>> index 7b36976..60daab4 100644
>> --- a/kernel/resource.c
>> +++ b/kernel/resource.c
>> @@ -451,7 +451,7 @@ static struct resource * __insert_resource(struct resource *parent, struct resou
>>               if (!first)
>>                       return first;
>>
>> -             if (first == parent)
>> +             if (first == parent || first == new)
>>                       return first;
>
> However, inserting the same thing twice _is_ a bug, and we shouldn't
> silently accept it like this.  We should tell the programmer!

Indeed, this is a bug caused by the driver programmer.I had spent
nearly two day to find it in my colleague's code.


>
> But we can recover from the situation so let's not kill the box.  How
> does this look?
>
> --- a/kernel/resource.c~kernel-resourcec-handle-reinsertion-of-an-already-inserted-resource
> +++ a/kernel/resource.c
> @@ -453,6 +453,8 @@ static struct resource * __insert_resour
>
>                if (first == parent)
>                        return first;
> +               if (WARN_ON(first == new))      /* duplicated insertion */
> +                       return first;
>

Yes. This one is better.
Many drivers do not check the returned value of insert_resouce().


>                if ((first->start > new->start) || (first->end < new->end))
>                        break;
> _
>
>
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