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SubjectRe: [PATCH 1/5] v2 Split the memory_block structure
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On Fri, 2010-07-16 at 13:23 -0500, Nathan Fontenot wrote:
> >> - if (mem->state != from_state_req) {
> >> - ret = -EINVAL;
> >> - goto out;
> >> + list_for_each_entry(mbs, &mem->sections, next) {
> >> + if (mbs->state != from_state_req)
> >> + continue;
> >> +
> >> + ret = memory_block_action(mbs, to_state);
> >> + if (ret)
> >> + break;
> >> + }
> >> +
> >> + if (ret) {
> >> + list_for_each_entry(mbs, &mem->sections, next) {
> >> + if (mbs->state == from_state_req)
> >> + continue;
> >> +
> >> + if (memory_block_action(mbs, to_state))
> >> + printk(KERN_ERR "Could not re-enable memory "
> >> + "section %lx\n", mbs->phys_index);
> >> + }
> >> }
> >
> > Please just use a goto here. It's nicer looking, and much more in line
> > with what's there already.
>
> Not sure if I follow on where you want the goto. If you mean after the
> if (memory_block_action())... I purposely did not have a goto here.
> Since this is in the recovery path I wanted to make sure we tried to return
> every memory section to the original state.

Looking at it a little closer, I see what you're doing now.

First of all, should memory_block_action() get a new name since it isn
not taking 'memory_block_section's?

The thing I would have liked to see is to have that error handling block
out of the way a bit. But, the function is small, and there's not _too_
much code in there, so what you have is probably the best way to do it.

Minor nit: Please pull the memory_block_action() out of the if() and do
the:

> >> + ret = memory_block_action(mbs, to_state);
> >> + if (ret)
> >> + break;

thing like above. It makes it much more obvious that the loop is
related to the top one. I was thinking if it made sense to have a
helper function to go through and do that list walk, so you could do:

ret = set_all_states(mem->sections, to_state);
if (ret)
set_all_states(mem->sections, old_state);

But I think you'd need to pass in a bit more information, so it probably
isn't worth doing that, either.

-- Dave



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