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    SubjectRe: [PATCH 0/5] ftrace: to kill a daemon

    On Fri, 8 Aug 2008, Steven Rostedt wrote:
    > Can a processor be preempted in a middle of nops?

    Sure. If you have two nops in a row (and the kernel definition of the NOP
    array does _not_ guarantee that it's a single-instruction one), you may
    get a profile hit (ie any interrupt) on the second one. It's less
    _likely_, but it certainly is not architecturally in any way guaranteed
    that the kernel "nop[]" tables would be atomic.

    > What do nops do for a processor?

    Depends on the microarchitecture. But many will squash it in the decode
    stage, and generate no uops for them at all, so it's purely a decode
    throughput issue and has absolutely _zero_ impact for any later CPU

    > Can it skip them nicely in one shot?

    See above. It needs to decode them, and the decoder itself may well have
    some limitations - for example, the longer nops may not even decode in all
    decoders, which is why some uarchs might prefer two short nops to one long
    one, but _generally_ a nop will not make it any further than the decoder.
    But separate nops do count as separate instructions, ie they will hit all
    the normal decode limits (mostly three or four instructions decoded per

    > I'm assuming that jmp is more expensive than the nops because otherwise
    > a jmp 0 would have been used as a 5 byte nop.

    Yes. A CPU core _could_ certainly do special decoding for 'jmp 0' too, but
    I don't know any that do. The 'jmp' is much more likely to be special in
    the front-end and the decoder, and can easily cause things like the
    prefetcher to hickup (ie it tries to start prefetching at the "new" target

    So I would absolutely _expect_ a 'jmp' to be noticeably more expensive
    than one of the special nop's that can be squashed by the decoder.

    A nop that is squashed by the decoder will literally take absolutely no
    other resources. It doesn't even need to be tracked from an instruction
    completion standpoint (which _may_ end up meaning that a profiler would
    actually never see a hit on the second nop, but it's quite likely to
    depend on which decoder it hits etc).


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