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SubjectRe: gcc fixed size char array initialization bug - known?
On Thu, 2 Aug 2007, Robert Hancock wrote:

> Because 5 characters will not fit in a 4 character array, even without the
> null terminator.

On Fri, 3 Aug 2007, Stefan Richter wrote:

> How should gcc know whether you actually wanted that char foo[len] to
> contain a \0 as last element?

Robert, Stefan, I am sorry, I think, you are VERY wrong here. There is no
"even" and no guessing. The "string" DOES include a terminating '\0'. It
is EQUIVALENT to {'s', 't', 'r', 'i', 'n', 'g', '\0'}. And it contains
SEVEN characters. Please, re-read your K&R. Specifically, the Section
"Initialization" in the "Function and Program Structure" chapter (section
4.9 in my copy), the paragraph about initialization with a string, which I
quoted in an earlier email.

And, Stefan, there is a perfect way to specify a "0123" without the '\0' -
{'0', '1', '2', '3'}.

Guennadi Liakhovetski
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