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    Subject[RFC] fs/super.c: Why alloc_super use a static variable default_op?
    Why alloc_super use a static variable default_op?
    the static struct super_operations default_op is just all zeros, and
    just referenced as the initial value of a new allocated super_block,
    what does it for?

    the filesystem dependent code such as ext2_fill_super would fill this
    field eventually,
    and after carefully checked, it seems no one filesystem would need a
    all zero default_op,

    as the command output in the kernel source tree:
    $ grep -RInw s_op fs/
    You could check all the use of s_op.

    * alloc_super - create new superblock
    * @type: filesystem type superblock should belong to
    * Allocates and initializes a new &struct super_block. alloc_super()
    * returns a pointer new superblock or %NULL if allocation had failed.
    static struct super_block *alloc_super(struct file_system_type *type)
    struct super_block *s = kzalloc(sizeof(struct super_block), GFP_USER);

    static struct super_operations default_op;

    if (s) {
    s->s_op = &default_op;
    s->s_time_gran = 1000000000;
    return s;

    Denis Cheng
    Linux Application Developer

    "One of my most productive days was throwing away 1000 lines of code."
    - Ken Thompson.
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      Last update: 2007-07-25 05:51    [W:0.019 / U:4.648 seconds]
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