Messages in this thread | | | Date | Sat, 21 Jul 2007 06:32:56 +0200 | Subject | Fixing lables after GNU indent (Re: [PATCH 1/2] run scripts/Lindent on it to match Documentation/CodingStyle) | From | Oleg Verych <> |
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[] > > > sed -i -e 's/^\t* \(\w*:\)/ \1/' "$@" > > > > > > which will replace the leading tabs and spaces with one space. > > > It should leave case labels unmolested, as they should be indented with > > > tabs, not 6 spaces. > > > > > > Any regexp ninjas want to have a go at something better? > > > > I'm the one. Trying to write portable, optimized and easy to > > understand scripts [0]. > > > > Please, describe more what must be done, and i will do it. Case labels > > are handled very strangely in you example. > > OK. indent will indent labels to a column number that's a multiple of > 8, plus 6. So it may start in column 6, 14, 20, 28, etc. I'm not quite > sure what the definition of a label is; I had it as \w*: up there, but I > don't know if that would match the _. The point is to *not* handle case > labels, only goto labels.
t=`printf '\t'` sed -i "s_^\($t*\) *\([^:]*:\)_\1\2_" "$@" ^-_ I'm not sure about leaving one space `here, otherwise it removes spaces between (supposedly right indented) line start, i.e. nothing or tab(s), and a label, i.e. `label_name:' without space before colon; `label_name' here actually not a colon, let's leave that kind of breakage to compiler.
The variable $t is used for readability of the regex and because POSIX BREs leave undefined characters after a backslash, POSIX sed defines only \n as a new line.
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