Messages in this thread | | | Date | Fri, 20 Jul 2007 05:07:25 -0700 (PDT) | From | Misbah khan <> | Subject | Re: workqueue is not working? |
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I didnt got very clearly what you actually did. But i guess you did faced some problem to work with work queue ( Bottom half of the handler ) I suggest you with an example code so that you could try with it and hope your doubt would get cleared.
/* work queue register and initialize */ static DECLARE_WORK(queue_name,(void *)func_name,func_arq_ptr);
eg :-
static DECLARE_WORK(my_queue,(void *)my_func,NULL);
/* In the Interrupt handler you need to call the bottom half of the function */
schedule_work(&my_queue);
/* The function defination is like this */ void my_func(void) { printk(" Hello from kernal land \n"); }
I hope this example will make your code to work for you , for any clarification please let me know
thanks
Xin Zhao wrote: > > I tried to schedule some work in an softirq handler. The way I did is > as follows: > > I use create_workqueue to initialize a workqueue "vrpciod_workqueue", > > in the softirq, I do INIT_WORK(work, func, data), and then > queue_work(vrpciod_workqueue, work); > > I think func() should be called a bit later. However, I noticed that > func() is never called by the workqueue. I don't know why. > > Can soneone give me some suggestions? Many thanks! > > Xin > - > To unsubscribe from this list: send the line "unsubscribe linux-kernel" in > the body of a message to majordomo@vger.kernel.org > More majordomo info at http://vger.kernel.org/majordomo-info.html > Please read the FAQ at http://www.tux.org/lkml/ > >
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