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SubjectRe: Segfault on the i386 enter instruction
linux-os (Dick Johnson) wrote:
> On Fri, 12 May 2006, Tomasz Malesinski wrote:
>> The code attached below segfaults on the enter instruction. It works
>> when a stack frame is created by the three commented out
>> instructions and also when the first operand of the enter instruction
>> is small (less than about 6500 on my system).
>> AFAIK, the only difference between creating a stack frame with the
>> enter instruction or push/mov/sub is that enter checks if the new
>> value of esp is inside the stack segment limit.
>> I tested it on a vanilla kernel 2.4.26 on Intel Celeron and also on
>> probably non-vanilla running on 3 dual core AMD Opteron,
>> quite busy, server. It is working in 32-bit mode. Interestingly, on
>> the second machine sometimes the program worked correctly.
>> I am not subscribed to the list. Please cc replies to me.
>> .file "a.c"
>> .version "01.01"
>> gcc2_compiled.:
>> .section .rodata
>> .LC0:
>> .string "asdf\n"
>> .text
>> .align 4
>> .globl main
>> .type main,@function
>> main:
>> enter $10008, $0
>> # pushl %ebp
>> # movl %esp,%ebp
>> # subl $10008,%esp
>> addl $-12,%esp
> ^^^^^^^^^^^^^^____________ WTF
> adding a negative number is subtracting that positive value.
Right, adding -12 is the same as subtracting 12. I have no idea what
you're getting at with the next two lines.
> You just subtracted 0xfffffff3 (on a 32-bit machine) from
> the stack pointer. It damn-well better seg-fault!
No, we subtracted 12. I'm not sure where that number came from, it's the
1's complement of 12 but I'm dead sure Linux code isn't running on any
1's comp machines.

-bill davidsen (
"The secret to procrastination is to put things off until the
last possible moment - but no longer" -me
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