Messages in this thread | | | Date | Fri, 3 Nov 2006 15:19:09 +0100 (CET) | From | Mikulas Patocka <> | Subject | Re: New filesystem for Linux |
| |
>> Really it can batch any number of modifications into one transaction >> (unless fsync or sync is called). Transaction is closed only on >> fsync/sync, if 2 minutes pass (can be adjusted) or when the disk runs out >> of space. > > Interesting. Let me pick an example and see where we're going from > there. You have four directories, A, B, C and D, none of which is the > parent of another. Two cross-directory renames happen: > $ mv A/foo B/ > $ mv C/bar D/ > > This will cause four modifications, one to each of the directories. I > would have assumed that the modifications to A and B receive one > transaction number n, C and D get a different one, n+1 if nothing else > is going on in between.
They most likely receive the same transaction (this is not like journaling transaction --- new transactions are issued only on conditions above).
A/foo entry is set with txc=memory_cct[memory_cc],cc=memory_cc B/foo entry is set with txc=memory_cct[memoty_cc]|0x80000000,cc=memory_cc C/foo entry is set with txc=memory_cct[memory_cc],cc=memory_cc D/foo entry is set with txc=memory_cct[memoty_cc]|0x80000000,cc=memory_cc
They may be written in any order (that's some improvement over journaling) by buffer thread.
And when you sync, with one write of memory_cct to disk, you make old entries permanently invalid and new entries permanently valid.
If the machine crashes before sync (and some of directory sectors were written and some not), new entries will always be considered invalid, and old entries always valid, because new crash count will be used and crash count table at old crash count index will never be modified.
> To commit the first rename, n is written into cct[entry->cc]. To > commit both, n+1 is written instead. Committing the second > transaction without committing the first is not possible. > > Now clearly we are disagreeing, so I must have misunderstood your > design somehow. Can you see how? > > Jörn
Mikulas | |