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SubjectRe: incorrect taint of ndiswrapper
On Mon, 23 Oct 2006 19:43:47 -0700 (PDT) Giridhar Pemmasani wrote:

> --- Alan Cox <alan@lxorguk.ukuu.org.uk> wrote:
>
> > Taint is used to identify situations where debug data may not be good,
> > that may be proprietary or other dubiously legal code, it may be forcing
> > SMP active on non SMP suitable systems, it may be overriding certain
> > options in a potentially hazardous fashion. Taint exists primarily to
> > help debugging data analysis.
>
> I have read the history of the patch that marked ndiswrapper as "proprietary
> module", which is not correct (and that was the point of my original post).
> All the posts realted to this referred to issues with loading binary code
> into kernel (and since ndiswrapper does taint the kernel when a driver is
> loaded, this again is misplaced).

The kernel should not depend on a not-in-tree kernel module to
taint the kernel. The kernel can and should do that itself.

(big) If ndiswrapper were ever added to the kernel tree, then that would
be a reasonable place to do/add the tainting.

> > EXPORT_SYMBOL_GPL() is used to assert that the symbol is absolutely
> > definitely not a public symbol. EXPORT_SYMBOL exports symbols which
> > might be but even then the GPL derivative work rules apply. When you
> > mark a driver GPL it is permitted to use _GPL symbols, but if it does so
> > it cannot then go and load other non GPL symbols and expect people not
> > to question its validity.
>
> I was not fully aware of this issue until now (I have read posts related to
> this issue now). Does this mean that any module that loads binary code can't
> be GPL, even those that load firmware files? How is
> non-GPL-due-to-transitivity going to be checked? Why does module loader mark
> only couple of modules as non-GPL, when there are other drivers that load
> some sort of binary code? It is understandable to mark a module as non-GPL if
> it is lying about its license, but as far as that is concerned, ndiswrapper
> (alone) is GPL.

---
~Randy
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