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SubjectRe: Ordered Sorted List
Nanakos Chrysostomos wrote:

>Hi ,all.Can someone please explain this source code with an example???
>
>
>
Homework?

>***********************************************************************
>#include <stdio.h>
>
>typedef struct list_tag {
> int data;
> struct list_tag *next;
>}ListNode;
>
>typedef ListNode *slist;
>slist empty = NULL;
>
>void slistInsert(slist *sp,int t)
>{
> ListNode *n=(ListNode *)malloc(sizeof(ListNode));
> if(n == NULL)
> {
> printf("Out of memory\n");
> exit(1);
> }
> n->data = t;
> while(*sp!=NULL && (*sp)->data < t)
> {
> sp = &((*sp)->next); //Why we do this here,i miss this point
> }
>
>
This is a _sorted_ list, right. So somehow we have to sort it.
What it does is to either find a node with a value higher then 't', or
it reach the end of the list. Meanwhile, it just continue walking the list.

> n->next = *sp;
> *sp = n;
>
>
... so here we hock the rest of the list with the new node.

>}
>
>
>void slistRemove(slist *sp,int t)
>{
> ListNode *n;
> while(*sp!=NULL && (*sp)->data <t)
> sp = &((*sp)->next);
> if(*sp == NULL)
> {
> printf("Not found\n");
> exit(1);
> }
>
> n=*sp;
> *sp = (*sp)->next;
> free(n);
>}
>
>void slistPrint(slist s)
>{
> ListNode *n;
> for(n=s;n!=NULL; n=n->next)
> printf("%d\n",n->data);
>}
>
>void main()
>{
>
>
>
NULL

> slistInsert(&empty,4);
>
>
4->NULL

> slistInsert(&empty,8);
>
>
4->8->NULL

> slistInsert(&empty,24);
>
4->8->24->NULL

> slistInsert(&empty,50);
>
>
4->8->24->50->NULL

> slistInsert(&empty,20);
>
>
4->8->20->24->50->NULL

> slistInsert(&empty,2);
>
>
2->4->8->20->24->50->NULL

> slistRemove(&empty,4);
>
>
Remove first value equal or more than 4.
2->8->20->24->50->NULL

> slistInsert(&empty,18);
>
>
2->8->18->20->24->50->NULL

> slistPrint(empty);
>
>
2
8
18
20
24
50

>}
>
>Thank you very much in advance.
>
>
cu
/Richard Knutsson
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