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SubjectRe: Why does the kernel need a gig of VM?
Hash: SHA1


I'd heard that there was a way to set 3.5/0.5 GiB split, and that there
was a patch that removed the split and isolated the kernel (but that was
slow), so I was just curious about all this stuff with people screaming
about how tight 4G of VM is vs a half gig or a gig that can be freed up.

Josh Boyer wrote:
> On Fri, 2005-01-28 at 15:06 -0500, John Richard Moser wrote:
>>Hash: SHA1
>>Can someone give me a layout of what exactly is up there? I got the
>>basic idea
>>K 4G
>>A 3G
>>A 2G
>>A 1G
>>App has 3G, kernel has 1G at the top of VM on x86 (dunno about x86_64).
>>So what's the layout of that top 1G? What's it all used for? Is there
>>some obscene restriction of 1G of shared memory or something that gets
>>mapped up there?
>>How much does it need, and why? What, if anything, is variable and
>>likely to do more than 10 or 15 megs of variation?
> Because of various reasons. Normal kernel space virtual addresses
> usually start at 0xc0000000, which is where the 3GiB userspace
> restriction comes from.
> Then there is the vmalloc virtual address space, which usually starts at
> a higher address than a normal kernel address. Along the same lines are
> ioremap addresses, etc.
> Poke around in the header files. I bet you'll find lots of reasons.
> josh

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