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SubjectRe: Lockless file reading
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On Thursday, Aug 28, 2003, at 04:50 Europe/Helsinki, Jamie Lokier wrote:

>> checksum[0]++;
>> xor = buf[0] ^ checksum[0];
>
> Your algorithm isn't going to work if the new value of xor is the same
> as the old value of xor.

I was trying to prevent it with the checksum[0]++ .. but yes, you're
right.

I'm sure someone has figured out a way to make a checksum of data that
can detect if there's even a single bit wrong, if the checksum is
allowed to take as much space as the data itself. I should read more
about algorithms..

How about checksum[n] = data[n-1] ^ data[n]? That looks like it would
work.

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