Messages in this thread Patch in this message | | | Subject | [patch] task_prio() fix | From | Robert Love <> | Date | 20 Feb 2003 18:42:40 -0500 |
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Looks like task_prio() should do:
int task_prio(task_t *p) { return p->prio - MAX_RT_PRIO; }
Instead of subtracting MAX_USER_RT_PRIO, since the maximum _user_ value has nothing to do with the maximum that may be stored. The effect is if MAX_RT_PRIO != MAX_USER_RT_PRIO, then all priorities are skewed by (MAX_RT_PRIO - MAX_USER_RT_PRIO).
Ingo, this looks trivial to me... but I swear it _used_ to work and this function has always been like this. Comments?
Patch is against 2.5.62.
Robert Love
kernel/sched.c | 2 +- 1 files changed, 1 insertion(+), 1 deletion(-)
diff -urN linux-2.5.62/kernel/sched.c linux/kernel/sched.c --- linux-2.5.62/kernel/sched.c 2003-02-20 18:30:08.232619488 -0500 +++ linux/kernel/sched.c 2003-02-20 18:30:15.585501680 -0500 @@ -1552,7 +1552,7 @@ */ int task_prio(task_t *p) { - return p->prio - MAX_USER_RT_PRIO; + return p->prio - MAX_RT_PRIO; } /**
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