Messages in this thread |  | | Date | Sun, 15 Sep 2002 21:34:10 +0200 | From | Willy Tarreau <> | Subject | Re: [BUG?] binfmt_script: interpreted interpreter doesn't work |
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On Sun, Sep 15, 2002 at 09:13:30PM +0200, Pozsar Balazs wrote:
> This is because the kernel cannot execute the "/home/pozsy/b" script, and > then bash tries to interpret it itself. (but this in *not* what I want: I > want the "b" 'script' interpreted by the "a" script). > If you try this: > strace -f /home/pozsy/b > You will get this: > execve("/home/pozsy/b", ["/home/pozsy/b"], [/* 24 vars */]) = 0 > strace: exec: Exec format error > > The root of the problem is still that /home/pozsy/b cannot be execve'd. > That is a kernel problem.
the problem is far simpler : when you execute /home/pozsy/b, the kernel should have to launch /home/pozsy/a with /home/pozsy/b in argv[0]. If it accepted to run it, it would run sh (or perl or any other interpreter) with /home/pozsy/a in argv[0], thus loosing track of /home/pozsy/b.
The simplest solution for you is to write a little C wrapper to start your interpreted interpreter with the script in argument. Written with dietlibc or anything like it, it would not be more than a few hundred bytes long.
Cheers, Willy
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