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    SubjectRe: Bug in kernel code?
    On 27 Aug 2002 at 17:23, David S. Miller wrote:

    > From: "Stephen C. Biggs" <>
    > Date: Tue, 27 Aug 2002 17:24:19 -0700
    > ........... Notice the --order >=0 in the do while test... since order is declared as an unsigned
    > long, this test is a pointless comparison and never fails, causing an infinite loop if the
    > hashtable is empty.
    > My fix to this is to change the test to have
    > while (dentry_hashtable == NULL && order-- != 0);
    > Could someone check me on this?
    > Your analysis is right but the fix is wrong, we do want to
    > try order == 0 on very small memory systems, and you should
    > not decrement the order at the beginning of the loop. We
    > want to use the "order" calculated.
    > Just make 'order' signed long to fix this bug.

    NO! That won't work either. This is a "do while" loop so the first test is always done and if
    order is 0, the check will be done AFTER the decrement, so this works. Changing it to a signed
    long loses you a bit.
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