Messages in this thread |  | | Date | Thu, 8 Feb 2001 21:09:49 -0800 (PST) | From | dean gaudet <> | Subject | ARP out the wrong interface |
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this appears to occur with both 2.2.16 and 2.4.1.
server:
eth0 is 192.168.250.11 netmask 255.255.255.0 eth1 is 192.168.251.11 netmask 255.255.255.0
they're both connected to the same switch.
client:
eth0 is 192.168.251.11 netmask 255.255.255.0
connected to the same switch as both of server's eth.
on client i try "ping 192.168.251.11".
responses come back from both eth0 and eth1, listing each of their respective MAC addresses... it's essentially a race condition at this point as to whether i'll get the right MAC address. ("right" means the MAC for server:eth1).
client# tcpdump -n arp Kernel filter, protocol ALL, datagram packet socket tcpdump: listening on all devices 21:03:05.695089 eth0 > arp who-has 192.168.251.11 tell 192.168.251.25 (0:3:47:0:25:80) 21:03:05.695405 eth0 < arp reply 192.168.251.11 is-at 0:d0:b7:be:3e:aa (0:3:47:0:25:80) 21:03:05.695523 eth0 < arp reply 192.168.251.11 is-at 0:d0:b7:1f:ea:35 (0:3:47:0:25:80)
server# cat /proc/sys/net/ipv4/ip_forward 0 server# cat /proc/sys/net/ipv4/conf/*/proxy_arp 0 0 0 0 0 0 0
is this expected? it seems broken.
thanks -dean
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