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    SubjectRe: [OFFTOPIC] Re: disk head scheduling
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    : > > "Richard B. Johnson" <root@chaos.analogic.com> writes:
    : > > > [snip]
    : > > > Expensive disk drives now do full track buffering. This costs
    : > > > money because RAM costs money. To buffer one full track on a
    : > > > Disc drive requires CAPACITY / (HEADS * CYLINDERS) which can
    : > > > be upwards of 100 megabytes of high-speed SRAM.

    You are confusing a track with a cylinder. A track sits on one platter
    and is typically quite small. A cylinder is the same track on multiple
    platters, and I don't know of any drives which buffer all tracks in a
    cylinder at the same time. In fact, I'll bet long odds that none do.
    Here's why. If the drive manufactors could read all tracks at the same
    time, they would do so. That would bump the drive speed from the current
    platter speed to N_HEADs * (platter speed), which would be extremely nice.

    However, they can't do that. The tracks within the same cylinder are not
    all at exactly the same place. Depending on which platter you are going for,
    the heads settle at a slightly different place. Very annoying that. If it
    weren't for that little problem, we could have 5 platter drives which were
    65MByte/sec drives.

    Anyway, the point is that nobody puts 100MB of buffer on their drives.
    I know Quantum is thinking about fairly large buffers but I think those
    are more like 32MB, and regardless, the reason for big buffers is not to
    buffer a cylinder (as nice as that would be).

    --lm

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