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SubjectRe: [PATCH RFC] MIPS: Remove detect_memory_region()
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On 02/24/2021 11:40 PM, Jiaxun Yang wrote:

>
> On Wed, Feb 24, 2021, at 9:02 PM, Jinyang He wrote:
>> detect_memory_region() was committed by Commit 4d9f77d25268 ("MIPS: add
>> detect_memory_region()"). Then it was equipped by Commit dd63b00804a5
>> ("MIPS: ralink: make use of the new memory detection code") and
>> Commit 9b75733b7b5e ("MIPS: ath79: make use of the new memory detection
>> code"). Its code is based on early ath79 platform code.
>>
>> What puzzles me is that how memcmp() detect the memory region. If `break`
>> was touched, the function could make sense. That means memcmp() should
>> return zero. Otherwise, the loop will be end by size > sz_max.
>>
>> I have tested detect_memory_region() on Loongson64 3A3000. On our design,
>> kseg0 low 256MB maps real memory and kseg0 high 256MB maps IO/PCI. The
>> function runs and last stopped on kseg1 where is uncached. In this process
>> memcmp also returned non-zero when detected kseg0 high 256MB. Then I did
>> another thing. memcpy first and test memcmp then (after &_end). It works
>> well on 3A3000 but badly on 3A4000. Maybe because kseg0 high 256MB maps
>> IO/PCI and it is dangerous to write like write memory.
>>
>> At last, read memory from where is not memory region may always return 0.
>> (Or trigger exception.) This function have been used several years and
>> seems no error occur. Maybe it's a fallback way.
> That is not true for other platforms like ath79 or mtk.
> They'll wrap around or return 0xffffffff for out of boundary accessing.
>
> Loongson does not apply to this case as it have special "Address Window"
> design to accurately describe address regions.
> Any access beyond described windows will be handled by MC and return 0 or random stuff.
>
> Again, please don't make changes because you can.
>
> Thanks.
>
> - Jiaxun

Hi, Jiaxun,

Thank you for answering this puzzle for me in detail.

Assume that the machine has 8MB real memory and dm address is (base + 3M).
When size = 8MB, there will be a phenomenon of `wrap around`, the actual
content of (dm + 8M + 3M) is content of (dm + 3M), so it will trigger
`break`, right? At this time, the kernel will add 8M to the memory.

Thanks,
Jinyang

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