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SubjectRe: xt_hashlimig build error (was Re: [RFC 01/17] x86/asm/64: Remove the restore_c_regs_and_iret label)
On 09/07/2017 02:43 PM, Linus Torvalds wrote:
> Note: that patch has *exactly* the issue I was talking about above.
> Doing that
> if (user > 0xFFFFFFFFULL)
> return 0;
> is different from the old code, which used to result in a zero in the
> divide, and then
> r = (r - 1) << 4;
> would cause it to return a large value.
> So the patch in question doesn't just fix the build error, it
> completely changes the semantics of the function too.
> I *think* the new behavior is likely what you want, but these kinds of
> things should be _described_.
> Also, even with the patch, we have garbage:
> 0xFFFFFFFFULL / (u32)user
> why is that sub-expression pointlessly doing a 64-bit divide with a
> 32-bit number? The compiler is hopefully smart enough to point things
> out, but that "ULL" really is _wrong_ there, and could cause a stupid
> compiler to still do a 64-bit divide (although hopefully the simpler
> version that is 64/32).
> So please clarify both the correct behavior _and_ the actual typing of
> the divide, ok?
> Linus

The value of 'user' is sent from userspace, which is the return value of
this function:

static uint64_t bytes_to_cost(uint32_t bytes)
uint32_t r = bytes >> XT_HASHLIMIT_BYTE_SHIFT;
return UINT32_MAX / (r+1);

What user2rate_bytes() is trying to do is the opposite of above. The
size of 'user' is 64bit for a different reason altogether, but in this
case it is guaranteed to be always < U32_MAX. And hence using 64bit
divide is completely pointless (which I now realize).

Writing U32INT_MAX as 0xFFFFFFFFULL was a mistake on my part. I could
have avoided all of this by using built-in constants instead of trying
to define them myself. I will rewrite the function as below and send out
another patch:

static u64 user2rate_bytes(u64 user)
u64 r;

r = user ? U32_MAX / (u32) user : U32_MAX;
return r;


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