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SubjectRe: security, hugetlbfs: write to user memory in hugetlbfs_destroy_inode
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Dmitry Vyukov wrote:
> On Thu, Mar 23, 2017 at 2:06 PM, Dmitry Vyukov <dvyukov@google.com> wrote:
> > Hello,
> >
> > I've got the following report while running syzkaller fuzzer on
> > 093b995e3b55a0ae0670226ddfcb05bfbf0099ae. Note the preceding injected
> > kmalloc failure in inode_alloc_security, most likely it's the root
> > cause.

I don't think inode_alloc_security() failure is the root cause.
I think this is a bug in hugetlbfs or mm part.

If inode_alloc_security() fails, inode->i_security remains NULL
which was initialized to NULL at security_inode_alloc(). Thus,
security_inode_alloc() is irrelevant to this problem.

inode_init_always() returned -ENOMEM due to fault injection and

if (unlikely(inode_init_always(sb, inode))) {
if (inode->i_sb->s_op->destroy_inode)
inode->i_sb->s_op->destroy_inode(inode);
else
kmem_cache_free(inode_cachep, inode);
return NULL;
}

hugetlbfs_destroy_inode() was called via inode->i_sb->s_op->destroy_inode()
when inode initialization failed

static void hugetlbfs_destroy_inode(struct inode *inode)
{
hugetlbfs_inc_free_inodes(HUGETLBFS_SB(inode->i_sb));
mpol_free_shared_policy(&HUGETLBFS_I(inode)->policy);
call_rcu(&inode->i_rcu, hugetlbfs_i_callback);
}

but mpol_shared_policy_init() is called only when new_inode() succeeds.

inode = new_inode(sb);
if (inode) {
(...snipped...)
info = HUGETLBFS_I(inode);
/*
* The policy is initialized here even if we are creating a
* private inode because initialization simply creates an
* an empty rb tree and calls rwlock_init(), later when we
* call mpol_free_shared_policy() it will just return because
* the rb tree will still be empty.
*/
mpol_shared_policy_init(&info->policy, NULL);

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