Messages in this thread | | | Date | Wed, 1 Nov 2017 21:20:18 +0900 | From | Stafford Horne <> | Subject | Re: [PATCH] openrisc: pass endianness info to sparse |
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On Wed, Nov 01, 2017 at 05:34:29AM +0100, Luc Van Oostenryck wrote: > On Wed, Nov 1, 2017 at 3:00 AM, Stafford Horne <shorne@gmail.com> wrote: > > On Tue, Oct 31, 2017 at 06:22:05PM +0100, Luc Van Oostenryck wrote: > >> openrisc is big-endian only but sparse assumes the same endianness > >> as the building machine. > >> This is problematic for code which expect __BYTE_ORDER__ being > >> correctly predefined by the compiler which sparse can then > >> pre-process differently from what gcc would, depending on the > >> building machine endianness. > >> > >> Fix this by letting sparse know about the architecture endianness. > > > > Thank You, > > > > I have applied this. I haven't really used sparse before, but it looks great. > > Just use 'make C=1' or 'make C=2' when compiling the kernel. > For endianness problems, sparse is invaluable as it does things no > others tools can.
Right, I tried it out and it works well. Now I have a new tool to add to my workflow, and it looks like a few bugs to fix as well.
> > Do you think openrisc needs to set other arguments like __BIG_ENDIAN__ as other > > architectures do? > > If you use a recent version of sparse (the version 0.5.1 released in August), > which I strongly advise, you don't need to as sparse then understand > -mbig-endian > and then define __BIG_ENDIAN__ internally, like GCC do. > But with older version of sparse, yes, it would also be needed as well > as __BYTE_ORDER__.
I do have 0.5.1 so I should be good.
-Stafford
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