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SubjectRe: [PATCH -v2 4/6] locking, arch: Update spin_unlock_wait()
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On 5/27/2016 5:05 AM, Peter Zijlstra wrote:
> On Thu, May 26, 2016 at 05:10:36PM -0400, Chris Metcalf wrote:
>> On 5/26/2016 10:19 AM, Peter Zijlstra wrote:
>>> --- a/arch/tile/lib/spinlock_32.c
>>> +++ b/arch/tile/lib/spinlock_32.c
>>> @@ -72,10 +72,14 @@ void arch_spin_unlock_wait(arch_spinlock
>>> if (next == curr)
>>> return;
>>> + smp_rmb();
>>> +
>>> /* Wait until the current locker has released the lock. */
>>> do {
>>> delay_backoff(iterations++);
>>> } while (READ_ONCE(lock->current_ticket) == curr);
>>> +
>>> + smp_acquire__after_ctrl_dep();
>>> }
>>> EXPORT_SYMBOL(arch_spin_unlock_wait);
>>> --- a/arch/tile/lib/spinlock_64.c
>>> +++ b/arch/tile/lib/spinlock_64.c
>>> @@ -72,10 +72,14 @@ void arch_spin_unlock_wait(arch_spinlock
>>> if (arch_spin_next(val) == curr)
>>> return;
>>> + smp_rmb();
>>> +
>>> /* Wait until the current locker has released the lock. */
>>> do {
>>> delay_backoff(iterations++);
>>> } while (arch_spin_current(READ_ONCE(lock->lock)) == curr);
>>> +
>>> + smp_acquire__after_ctrl_dep();
>>> }
>>> EXPORT_SYMBOL(arch_spin_unlock_wait);
>> The smp_rmb() are unnecessary for tile. We READ_ONCE next/curr from the
>> lock and compare them, so we know the load(s) are complete. There's no
>> microarchitectural speculation going on so that's that. Then we READ_ONCE
>> the next load on the lock from within the wait loop, so our load/load
>> ordering is guaranteed.
> Does TILE never speculate reads? Because in that case the control
> dependency already provides a full load->load,store barrier and you'd
> want smp_acquire__after_ctrl_dep() to be a barrier() instead of
> smp_rmb().

Yes, that's a good point. I didn't look at the definition of smp_acquire__after_ctrl_dep(),
but it certainly sounds like that's exactly a compiler barrier for tile. There is no load
speculation performed. The only out-of-order stuff that happens is in the memory
subsystem: stores will become visible in arbitrary order, and loads will arrive in
arbitrary order, but as soon as the result of a load is used in any other kind of
instruction, the instruction issue will halt until the pending load(s) for the instruction
operands are available.

--
Chris Metcalf, Mellanox Technologies
http://www.mellanox.com

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