lkml.org 
[lkml]   [2016]   [Feb]   [25]   [last100]   RSS Feed
Views: [wrap][no wrap]   [headers]  [forward] 
 
Messages in this thread
    /
    Date
    From
    SubjectRe: [PATCH tip/core/rcu 02/14] documentation: Fix control dependency and identical stores
    On Thu, Feb 25, 2016 at 09:21:43AM +0100, Peter Zijlstra wrote:
    > On Wed, Feb 24, 2016 at 01:40:13PM -0800, Paul E. McKenney wrote:
    > > > > + (*) If both legs of the "if" statement begin with identical stores to
    > > > > + the same variable, then those stores must be ordered, either by
    > > > > + preceding both of them with smp_mb() or by using smp_store_release()
    > > > > + to carry out the stores. Please note that it is -not- sufficient
    > > > > + to use barrier() at beginning of each leg of the "if" statement,
    > > > > + as optimizing compilers do not necessarily respect barrier()
    > > > > + in this case.
    >
    > > Let's take the example, replace barrier() with smp_mb(), and see what
    > > happens:
    > >
    > > q = READ_ONCE(a);
    > > if (q) {
    > > smp_mb();
    > > WRITE_ONCE(b, p);
    > > do_something();
    > > } else {
    > > smp_mb();
    > > WRITE_ONCE(b, p);
    > > do_something_else();
    > > }
    >
    > Why would an optimizing compiler be allowed to lift _anything_ over a
    > barrier() ? Isn't that a bug?
    >
    > I thought the whole point of barrier() was to tell the compiler to not
    > do such things.

    Still bad wording...

    It hasn't actually moved anything over the barrier(). It has instead
    moved both the barrier() and the WRITE_ONCE(b, p) to precede the "if
    (q)". Mathieu mentioned this over IRC yesterday, and I queue a change
    so that the paragraph now reads as follows:

    (*) If both legs of the "if" statement begin with identical stores to
    the same variable, then those stores must be ordered, either by
    preceding both of them with smp_mb() or by using smp_store_release()
    to carry out the stores. Please note that it is -not- sufficient
    to use barrier() at beginning of each leg of the "if" statement
    because, as shown by the example above, optimizing compilers can
    destroy the control dependency while respecting the letter of the
    barrier() law.

    Does hat help?

    Thanx, Paul

    \
     
     \ /
      Last update: 2016-02-25 15:41    [W:2.348 / U:0.032 seconds]
    ©2003-2020 Jasper Spaans|hosted at Digital Ocean and TransIP|Read the blog|Advertise on this site