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SubjectRe: [PATCH v10 3/4] cgroups: allow a cgroup subsystem to reject a fork
On Fri, Apr 24, 2015 at 11:59:31PM +1000, Aleksa Sarai wrote:
> Hey,
>
> >> +#define CGROUP_PREFORK_COUNT 0
> >> +
> >> static inline int cgroup_init_early(void) { return 0; }
> >> static inline int cgroup_init(void) { return 0; }
> >> static inline void cgroup_fork(struct task_struct *p) {}
> >> -static inline void cgroup_post_fork(struct task_struct *p) {}
> >> +static inline int cgroup_can_fork(struct task_struct *p,
> >> + void *s[CGROUP_PREFORK_COUNT])
> >> +{
> >> + return 0;
> >> +}
> >
> > Style consistency?
>
> It's because it wraps. I can move it to be something like:
>
> static inline int cgroup_can_fork(struct task_struct *p,
> void *s[CGROUP_PREFORK_COUNT])
> { return 0; }

static inline int cgroup_can_fork(struct task_struct *p,
void *s[CGROUP_PREFORK_COUNT])
{ return 0; }

> >> @@ -2078,6 +2084,18 @@ static void cgroup_task_migrate(struct cgroup *old_cgrp,
> >> list_move_tail(&tsk->cg_list, &new_cset->mg_tasks);
> >>
> >> /*
> >> + * We detach from the old_cset subsystems here. We must do this
> >> + * before we drop the refcount for old_cset, in order to make sure
> >> + * that nobody frees it underneath us.
> >> + */
> >> + for_each_e_css(css, i, old_cgrp) {
> >> + struct cgroup_subsys_state *old_css = old_cset->subsys[i];
> >> +
> >> + if (old_css->ss->detach)
> >> + old_css->ss->detach(old_css, tsk);
> >> + }
> >
> > I don't get this. What can ->detach do that ->can_attach cannot?
>
> ->detach signifies that a task is being migrated away from a cgroup.
> On second thought, we could just use task_css() on each task in the
> tset to figure out what the cgroup the task is being migrated away
> from is and just uncharge that inside ->can_attach.

Yeah, that's how it's supposed to be used. You have access to both
pre and post csses before migration and only to the new ones once by
the time ->attach() is running.

> On the same point, are all the tasks in a tset passed to ->can_attach
> guaranteed to have the same css? Or do I have to uncharge each one
> individually?

They're the same.

Thanks.

--
tejun

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