Messages in this thread | | | From | (Eric W. Biederman) | Date | Thu, 21 Feb 2013 17:55:27 -0800 | Subject | Re: [PATCH] kexec: prevent double free on image allocation failure |
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Sasha Levin <sasha.levin@oracle.com> writes:
> If kimage_normal_alloc() fails to initialize an allocated kimage, it will free > the image but would still set 'rimage', as a result kexec_load will try > to free it again. > > This would explode as part of the freeing process is accessing internal > members which point to uninitialized memory.
Agreed.
I don't think that failure path has ever actually been exercised.
The code is wrong, and it is worth fixing.
Andrew I do you think you could queue this up? I don't have a handy tree.
Reviewed-by: "Eric W. Biederman" <ebiederm@xmission.com> > Signed-off-by: Sasha Levin <sasha.levin@oracle.com> > --- > kernel/kexec.c | 2 -- > 1 file changed, 2 deletions(-) > > diff --git a/kernel/kexec.c b/kernel/kexec.c > index 2348bd6..855bfbb 100644 > --- a/kernel/kexec.c > +++ b/kernel/kexec.c > @@ -242,8 +242,6 @@ static int kimage_normal_alloc(struct kimage **rimage, unsigned long entry, > if (result) > goto out; > > - *rimage = image; > - > /* > * Find a location for the control code buffer, and add it > * the vector of segments so that it's pages will also be
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