Messages in this thread Patch in this message | | | Date | Mon, 2 Apr 2012 10:05:22 -0500 | From | Jonathan Nieder <> | Subject | [PATCH] x86: memtest: WARN if bad RAM found |
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From: Ben Hutchings <ben@decadent.org.uk> Date: Mon, 5 Dec 2011 04:00:58 +0000
Since this is not a particularly thorough test, if we find any bad bits of RAM then there is a fair chance that there are other bad bits we fail to detect.
Signed-off-by: Ben Hutchings <ben@decadent.org.uk> Signed-off-by: Jonathan Nieder <jrnieder@gmail.com> --- Hi,
The patch below comes from this discussion
http://bugs.debian.org/cgi-bin/bugreport.cgi?msg=50;bug=613321
and has been in use in Debian kernels since last December. The rationale does not seem particularly distro-specific, and all in all it looks to me like a good change.
Nothing urgent here. I imagine this patch as targetted to v3.5.
Thoughts? Jonathan
arch/x86/mm/memtest.c | 2 ++ 1 file changed, 2 insertions(+)
diff --git a/arch/x86/mm/memtest.c b/arch/x86/mm/memtest.c index c80b9fb95734..38caeb44a218 100644 --- a/arch/x86/mm/memtest.c +++ b/arch/x86/mm/memtest.c @@ -30,6 +30,8 @@ static u64 patterns[] __initdata = { static void __init reserve_bad_mem(u64 pattern, u64 start_bad, u64 end_bad) { + WARN_ONCE(1, "Bad RAM detected. Use memtest86+ to perform a thorough test\n" + "and the memmap= parameter to reserve the bad areas."); printk(KERN_INFO " %016llx bad mem addr %010llx - %010llx reserved\n", (unsigned long long) pattern, (unsigned long long) start_bad, -- 1.7.10.rc3
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