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    SubjectRe: [ANNOUNCEMENT] The Barbershop Load Distribution algorithm for Linux kernel scheduler.
    On Tue, Feb 14, 2012 at 1:22 AM, Rakib Mullick <> wrote:
    >>> +
    >>> +       if (rq->pos != 2) {     /* if rq isn't the last one */
    >>> +               struct rq *last;
    >>> +               write_lock_irqsave(&disp_list_lock, flag);
    >>                    if (rq->pos != 2)
    >>                             goto out;
    > At this point, we're checking whether this task is activating on a rq
    > which is the last (hightest loaded) rq or not. If rq->pos != 2, it
    > stands we're not activating a task at the highest loaded rq, so a
    > check will be made with the highest loaded rq to make sure - this rq's
    > loaded didn't exceed the highest loaded rq. If rq's load
    > exceed - list will be removed from it's place and will be placed as a
    > last entry of rq_head and thus it becomes the highest loaded rq. So,
    > what you proposed here isn't what was intended.

    I want to say
                       if (rq->pos == 2)
                                goto out;
    sorry for the bad:(

    > Hiff, did you ran the patch? Would like to know.

    Try to run soon.

    Best regards
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