lkml.org 
[lkml]   [2011]   [Aug]   [26]   [last100]   RSS Feed
Views: [wrap][no wrap]   [headers]  [forward] 
 
Messages in this thread
/
Date
From
SubjectRe: [PATCH 2/5] writeback: dirty position control
On Fri, Aug 26, 2011 at 04:56:11PM +0800, Peter Zijlstra wrote:
> On Fri, 2011-08-26 at 09:56 +0800, Wu Fengguang wrote:
> > /*
> > * A linear estimation of the "balanced" throttle rate. The theory is,
> > * if there are N dd tasks, each throttled at task_ratelimit, the bdi's
> > * dirty_rate will be measured to be (N * task_ratelimit). So the below
> > * formula will yield the balanced rate limit (write_bw / N).
> > *
> > * Note that the expanded form is not a pure rate feedback:
> > * rate_(i+1) = rate_(i) * (write_bw / dirty_rate) (1)
> > * but also takes pos_ratio into account:
> > * rate_(i+1) = rate_(i) * (write_bw / dirty_rate) * pos_ratio (2)
> > *
> > * (1) is not realistic because pos_ratio also takes part in balancing
> > * the dirty rate. Consider the state
> > * pos_ratio = 0.5 (3)
> > * rate = 2 * (write_bw / N) (4)
> > * If (1) is used, it will stuck in that state! Because each dd will be
> > * throttled at
> > * task_ratelimit = pos_ratio * rate = (write_bw / N) (5)
> > * yielding
> > * dirty_rate = N * task_ratelimit = write_bw (6)
> > * put (6) into (1) we get
> > * rate_(i+1) = rate_(i) (7)
> > *
> > * So we end up using (2) to always keep
> > * rate_(i+1) ~= (write_bw / N) (8)
> > * regardless of the value of pos_ratio. As long as (8) is satisfied,
> > * pos_ratio is able to drive itself to 1.0, which is not only where
> > * the dirty count meet the setpoint, but also where the slope of
> > * pos_ratio is most flat and hence task_ratelimit is least fluctuated.
> > */
>
> I'm still not buying this, it has the massive assumption N is a
> constant, without that assumption you get the same kind of thing you get
> from not adding pos_ratio to the feedback term.

The reasoning between (3)-(7) actually assumes both N and write_bw to
be some constant. It's documenting some stuck state..

> Also, I've yet to see what harm it does if you leave it out, all
> feedback loops should stabilize just fine.

That's a good question. It should be trivial to try out equation (1)
and see how it work out in practice. Let me collect some figures..

Thanks,
Fengguang


\
 
 \ /
  Last update: 2011-08-26 11:57    [W:0.211 / U:0.364 seconds]
©2003-2020 Jasper Spaans|hosted at Digital Ocean and TransIP|Read the blog|Advertise on this site