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SubjectRe: hackbench regression due to commit 9dfc6e68bfe6e
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On Thu, 2010-04-08 at 09:00 +0200, Eric Dumazet wrote:
> Le jeudi 08 avril 2010 à 07:39 +0200, Eric Dumazet a écrit :
> > I suspect NUMA is completely out of order on current kernel, or my
> > Nehalem machine NUMA support is a joke
> >
> > # numactl --hardware
> > available: 2 nodes (0-1)
> > node 0 size: 3071 MB
> > node 0 free: 2637 MB
> > node 1 size: 3062 MB
> > node 1 free: 2909 MB
> >
> >
> > # cat try.sh
> > hackbench 50 process 5000
> > numactl --cpubind=0 --membind=0 hackbench 25 process 5000 >RES0 &
> > numactl --cpubind=1 --membind=1 hackbench 25 process 5000 >RES1 &
> > wait
> > echo node0 results
> > cat RES0
> > echo node1 results
> > cat RES1
> >
> > numactl --cpubind=0 --membind=1 hackbench 25 process 5000 >RES0_1 &
> > numactl --cpubind=1 --membind=0 hackbench 25 process 5000 >RES1_0 &
> > wait
> > echo node0 on mem1 results
> > cat RES0_1
> > echo node1 on mem0 results
> > cat RES1_0
> >
> > # ./try.sh
> > Running with 50*40 (== 2000) tasks.
> > Time: 16.865
> > node0 results
> > Running with 25*40 (== 1000) tasks.
> > Time: 16.767
> > node1 results
> > Running with 25*40 (== 1000) tasks.
> > Time: 16.564
> > node0 on mem1 results
> > Running with 25*40 (== 1000) tasks.
> > Time: 16.814
> > node1 on mem0 results
> > Running with 25*40 (== 1000) tasks.
> > Time: 16.896
>
> If run individually, the tests results are more what we would expect
> (slow), but if machine runs the two set of process concurrently, each
> group runs much faster...
If there are 2 nodes in the machine, processes on node 0 will contact MCH of
node 1 to access memory of node 1. I suspect the MCH of node 1 might enter
a power-saving mode when all the cpus of node 1 are free. So the transactions
from MCH 1 to MCH 0 has a larger latency.

>
>
> # numactl --cpubind=0 --membind=1 hackbench 25 process 5000
> Running with 25*40 (== 1000) tasks.
> Time: 21.810
>
> # numactl --cpubind=1 --membind=0 hackbench 25 process 5000
> Running with 25*40 (== 1000) tasks.
> Time: 20.679
>
> # numactl --cpubind=0 --membind=1 hackbench 25 process 5000 >RES0_1 &
> [1] 9177
> # numactl --cpubind=1 --membind=0 hackbench 25 process 5000 >RES1_0 &
> [2] 9196
> # wait
> [1]- Done numactl --cpubind=0 --membind=1 hackbench
> 25 process 5000 >RES0_1
> [2]+ Done numactl --cpubind=1 --membind=0 hackbench
> 25 process 5000 >RES1_0
> # echo node0 on mem1 results
> node0 on mem1 results
> # cat RES0_1
> Running with 25*40 (== 1000) tasks.
> Time: 13.818
> # echo node1 on mem0 results
> node1 on mem0 results
> # cat RES1_0
> Running with 25*40 (== 1000) tasks.
> Time: 11.633
>
> Oh well...
>
>


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