Messages in this thread | | | Date | Thu, 11 Mar 2010 02:56:16 -0800 (PST) | From | Valery Reznic <> | Subject | execve for script don't return ENOEXEC, bug ? |
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Hi,
I Have following to scripts:
a.sh #!/bin/sh echo "It's a.sh
and b.sh: #! ./b.sh echo "It's b.sh"
As per execve man page, script interpreter should not be script itself. When I run it on my Fedora 8 x86_64 box (with stock kernel, never updated) under strace I got following:
strace -f -e execve setarch x86_64 ./b.sh execve("/usr/bin/setarch", ["setarch", "x86_64", "./b.sh"], [/* 23 vars */]) = 0 execve("./b.sh", ["./b.sh"], [/* 23 vars */]) = -1 ENOEXEC (Exec format error) execve("/bin/sh", ["/bin/sh", "./b.sh"], [/* 23 vars */]) = 0 It's b.sh
I.e execve failed as it should
When I run same scripts on Fedora 12 x86_64 box with stock kernel 2.6.31.5-127.fc12.x86_64 I got following:
strace -f -e execve setarch i386 ./b.sh execve("/usr/bin/setarch", ["setarch", "i386", "./b.sh"], [/* 41 vars */]) = 0 execve("./b.sh", ["./b.sh"], [/* 41 vars */]) = 0 It's a.sh
I.e execve succeeded, instead of failing with ENOEXEC
Regards, Valery.
P.S. I am not subscribed to this list, so please CC me
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